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28p^2-17p-3=0
a = 28; b = -17; c = -3;
Δ = b2-4ac
Δ = -172-4·28·(-3)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-25}{2*28}=\frac{-8}{56} =-1/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+25}{2*28}=\frac{42}{56} =3/4 $
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